Question

helpp on geometry

Answer 1

can you post your question?

Answer 2

This is it

Answer 3

#41?

Answer 4

and #42 if you can i put the pic of that question after if u want to do it with me

Answer 5

First, you want to solve for x.

And you know
<CDK + <KDE =<CDE

Can you set up the eqûation?

Answer 6

yes lemme do it for yu

Answer 7

30+14x-2=1+23x
28+14x=1+23x
-9x=17
x=-3

Answer 8

You made some algebraic error.
Should have gotten x=3

Answer 9

yes your right it is 3

Answer 10

Ok. Now plug in 3 for x to solve for <CDE

Answer 11

so its 70

Answer 12

Correct

Answer 13

so now can you help me with number 42

Answer 14

This is 42

Answer 15

Same thing.
Set up an equation and solve for x first

Answer 16

180+3x-10=-10+17x
170+3x=-10+17x
180=14x
x=12.8

Answer 17

Not quite.
It's <WDC + <WDE= <CDE

Answer 18

Because those two angles put together makes <CDE

Answer 19

3x-10-10x+17=180
-7x+7=180
-7

Answer 20

i got a decimal also

Answer 21

24.7

Answer 22

I think you're copying the problem wrong.

3x -10 -10 +17x=180

Answer 23

3x-10-10+17x=180
20x-20=180
20x=200
x=10

Answer 24

Correct. Now plug 10 for x and solve for <WDE

Answer 25

160

Answer 26

Correct

Answer 27

thank you so much i really appreciate it!!!!!!!!!!!!

Answer 28

No problem

Answer 29

this just made me finish my summer packet

Answer 30

and thanks for the medal too!!

Answer 31

Eww. You have summer hw