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For the function defined by f(x)= x^2 x=1 2x+1 x>1.... identify the function that will be used when x=0?
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\[f(x)=\begin{cases}x^2&\text{for }x\le1\\2x+1&\text{for }x>1\end{cases}\] Which part of the function is defined for \(x=0\)?
it says evaluate f(0)
Right, I get that, but I'm asking you which piece of the piecewise function applies to that value of \(x\)?
x^2 and 2x+1?
Let me ask you a different way: Is 0 less than 1 or greater than 1?
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less than
Okay, so which part of the given function is used for all numbers less than 1?
x^2?
Right, the rule for \(f(x)\) says for all values less than 1, it takes on \(f(x)=x^2\). So, since \(0<1\), you have \(f(0)=0^2=0\).
ohh, i get it
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thanks
yw
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