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r2-2rs+s2=4, (r-s)^6 ?
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did you mean (r-s)^2 ?
no its (r-s)^6
?? i don't understand the problem, are we solving for "r"
we are solving for (r-s)^6 that what will it be equalled to
Here is another.. if the ratio of area of 2 squares is 2:1 then what will be the ratio of circumference of circles?
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oh ok by factoring left side (r-s)^2 = 4 so (r-s)^6 = 4^3 = 64
thanks. Solve the other other plz
what .... how are the squares related to the circles?
i think it we have to find radius for both squares and then put in equations for the circumference
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