Question

Pre Calculus: Evaluate the following limits if they exists.

Answer 1

You need to use a known limit for first problem :
\[\large \lim \limits_{x\to 0}~ \dfrac{\sin x}{x} = 1\]

Answer 2

but x->pi/2 can i use that?

Answer 3

make a substitution :
\(\large x- \frac{\pi}{2} = t\)

Answer 4

as \(x \to \frac{\pi}{2} , t\to 0\) :

\[\large \lim \limits_{t \to 0} ~\dfrac{\sin (t)}{t}\]

Answer 5

oh I didn't know that. So answer is 1. What about question 4

Answer 6

@ganeshie8 could you help me with question 4 also?