Question

Help I will give medal Find an equation for the line with y-intercept 3 that is perpendicular to the line 3y = 2x-4.
A. 2y = 6-3x
B. 2y = 3x + 6
C. 3y = 9-2x
D. 3y = 2x + 9

Answer 1

2y=6-3x.

Answer 2

itas a long explanation... if you want i can explain it...

Answer 3

How did you get it

Answer 4

Remember if a line has the y-intercept 3, then it goes through the point (0,3)

Answer 5

two perpendicular lines are negative reciprocals of each other. So if you're given the slope of 2/3 you can find the perpendicular slope by this formula: m (underexponent) P=-1/m

Answer 6

So plug in the given slope to find the perpendicular slope one over 2/3
(-1/1)*(3/2) then multiply comin out with the anwser of (-3/2)

now we know the slope of the unknown line is -3/2 (its the negative reciprocal of 2/3 from the line

Answer 7

y=(2/3)*x-4 this is what you would plug in

y-y(underexponent) 1=m(x-x (underecponent)1 X underexponent 1 Yunderexponent 1

Answer 8

Then Plug in the following....


m =-3/2 X (underexponent) 1 =0 Y(unerexponent)1= 3

this is what its supposed to look like

y-3=(-3/2) *( X-0 )

Answer 9

multily the fractions and then you come out with the improper fractions and solve

Answer 10

coming out with 2y = 6-3x i hope this helped.. its eaiser if i can help one on one you know. may i please habe a metal now? :)

Answer 11

Thank you

Answer 12

no problem thanks for the metal

Answer 13

Your welcome