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Mathematics 19 Online
OpenStudy (anonymous):

HELP I'm stuck

OpenStudy (anonymous):

Choose the correct simplification of (2xy^2)^2(y^2)^3. 2x^2y^10 4x^2y^9 4x^2y^10 2x^2y^9

OpenStudy (anonymous):

what do you think it is?

OpenStudy (anonymous):

i believe that it is the third one

OpenStudy (anonymous):

I'm not sure, I figured it the first term to be to the power of 4.. so I'm totally lost on this

OpenStudy (anonymous):

well then im going to have to agree with @BVB4life that it would be the third one

OpenStudy (anonymous):

Okay, can you explain why orrr?

OpenStudy (anonymous):

2xy)^2(y^2)^3

OpenStudy (anonymous):

2^2*x^2(y^2)^2*y^2*^3

OpenStudy (anonymous):

then 2^2=4 so you get 4x^2y^10

OpenStudy (anonymous):

do you get it? or did i not explain it right?

OpenStudy (anonymous):

I got you now! Can you help with a little easier one?

OpenStudy (anonymous):

ya sure

OpenStudy (anonymous):

of course

OpenStudy (anonymous):

Choose the correct simplification of (4x - 3)(3x^2 - 4x - 3). 12x^3 + 25x^2 + 9 12x^3 - 25x^2 - 9 12x^3 + 25x^2 - 9 12x^3 - 25x^2 + 9

geerky42 (geerky42):

\((4x−3)(3x^2−4x−3)=[(4x)3x^2−(4x)4x−(4x)3]+[(-3)3x^2−(-3)4x−(-3)3]\)

OpenStudy (anonymous):

Breaks out of the comment box.. through the ad... and off into the distance..

geerky42 (geerky42):

Well, is that better? \((4x−3)(3x^2−4x−3)= \\ ~~~~~~~~~~~~[(4x)3x^2−(4x)4x−(4x)3]+\\ ~~~~~~~~~~~~[(-3)3x^2−(-3)4x−(-3)3]\)

OpenStudy (anonymous):

Yes! haha :)

geerky42 (geerky42):

do you know how I got this, right? I just distribute 4x and -3

OpenStudy (anonymous):

Right, so you get 12^3-16x-12x-9x^3-12x-9 combine like terms to get 12^3-21x^3-9??????

OpenStudy (anonymous):

I'm really confused... what's the answer then? :/

OpenStudy (anonymous):

Anyone???

OpenStudy (anonymous):

Please?

OpenStudy (anonymous):

i think it is the second one

OpenStudy (anonymous):

you just need to combine like terms to find your answer

OpenStudy (anonymous):

I tried but that's what I got

OpenStudy (anonymous):

you got the second one??

OpenStudy (anonymous):

No my other comment ^^^^

OpenStudy (anonymous):

Well thanks a ton @BVB4life , you show me the ways at math and maybe one day I'll show you the ways of real music ;P I'm just jokinngggggg

OpenStudy (anonymous):

But thanks hahaha xD

OpenStudy (anonymous):

lol your welcome :p

OpenStudy (anonymous):

thanks for fanning me

OpenStudy (anonymous):

Mhm!

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