Mathematics
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OpenStudy (anonymous):
HELP I'm stuck
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OpenStudy (anonymous):
Choose the correct simplification of (2xy^2)^2(y^2)^3.
2x^2y^10
4x^2y^9
4x^2y^10
2x^2y^9
OpenStudy (anonymous):
what do you think it is?
OpenStudy (anonymous):
i believe that it is the third one
OpenStudy (anonymous):
I'm not sure, I figured it the first term to be to the power of 4.. so I'm totally lost on this
OpenStudy (anonymous):
well then im going to have to agree with @BVB4life that it would be the third one
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OpenStudy (anonymous):
Okay, can you explain why orrr?
OpenStudy (anonymous):
2xy)^2(y^2)^3
OpenStudy (anonymous):
2^2*x^2(y^2)^2*y^2*^3
OpenStudy (anonymous):
then 2^2=4 so you get 4x^2y^10
OpenStudy (anonymous):
do you get it? or did i not explain it right?
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OpenStudy (anonymous):
I got you now! Can you help with a little easier one?
OpenStudy (anonymous):
ya sure
OpenStudy (anonymous):
of course
OpenStudy (anonymous):
Choose the correct simplification of (4x - 3)(3x^2 - 4x - 3).
12x^3 + 25x^2 + 9
12x^3 - 25x^2 - 9
12x^3 + 25x^2 - 9
12x^3 - 25x^2 + 9
geerky42 (geerky42):
\((4x−3)(3x^2−4x−3)=[(4x)3x^2−(4x)4x−(4x)3]+[(-3)3x^2−(-3)4x−(-3)3]\)
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OpenStudy (anonymous):
Breaks out of the comment box.. through the ad... and off into the distance..
geerky42 (geerky42):
Well, is that better?
\((4x−3)(3x^2−4x−3)= \\ ~~~~~~~~~~~~[(4x)3x^2−(4x)4x−(4x)3]+\\ ~~~~~~~~~~~~[(-3)3x^2−(-3)4x−(-3)3]\)
OpenStudy (anonymous):
Yes! haha :)
geerky42 (geerky42):
do you know how I got this, right? I just distribute 4x and -3
OpenStudy (anonymous):
Right, so you get 12^3-16x-12x-9x^3-12x-9
combine like terms to get 12^3-21x^3-9??????
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OpenStudy (anonymous):
I'm really confused... what's the answer then? :/
OpenStudy (anonymous):
Anyone???
OpenStudy (anonymous):
Please?
OpenStudy (anonymous):
i think it is the second one
OpenStudy (anonymous):
you just need to combine like terms to find your answer
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OpenStudy (anonymous):
I tried but that's what I got
OpenStudy (anonymous):
you got the second one??
OpenStudy (anonymous):
No my other comment ^^^^
OpenStudy (anonymous):
Well thanks a ton @BVB4life , you show me the ways at math and maybe one day I'll show you the ways of real music ;P I'm just jokinngggggg
OpenStudy (anonymous):
But thanks hahaha xD
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OpenStudy (anonymous):
lol your welcome :p
OpenStudy (anonymous):
thanks for fanning me
OpenStudy (anonymous):
Mhm!