Question

-2[square root of the 16(16)(-2) - (-2)^3(-1)] over
(2 - 6)^2

Answer 1

@Venny

Answer 2

Is this what you're asking?

Answer 3

-(Squareroot of 123/2)/4 would be the exact answer

Answer 4

no

Answer 5

@hhunny13

Answer 6

@math-geek

Answer 7

see it below...one moment,,

Answer 8

\[\frac{ -2\sqrt{16*16-2-8*-1} }{ (-4)^2 }=\frac{ -2\sqrt{256-2+8} }{ 16 }=\frac{ -\sqrt{262} }{ 8 }\]

Answer 9

ok

Answer 10

@zaibali.qasmi

Answer 11

yes,..???

Answer 12

its not 16 times 16

Answer 13

this is the quation

Answer 14

hold on

Answer 15

holding...