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Mathematics 17 Online
OpenStudy (johnnydicamillo):

Factor completely: 4v^4-6v^3-10v^2. I factored and got 2v^2(v^2-3v-5). Can I go further?

OpenStudy (anonymous):

v^2-3v-5 not factorable without imaginary numbers

OpenStudy (johnnydicamillo):

so I am correct then?

OpenStudy (anonymous):

Think so!

OpenStudy (anonymous):

I don't see any other way to do it

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