Question

What is the arc length if Θ = 6 pi over 5 and the radius is 2 cm?

Answer 1

@hartnn

Answer 2

arc length is just \(r \theta = 2 \times 6\pi/5 = ...\)

Answer 3

usE
S=R*THETA

here r=2cm and theta=6 pi /5

so S=(6 pi/5)*2=12pi/5=12*3.14/5=37.68/5=7.536cm

Answer 4

ohhh k thanks :)