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OpenStudy (anonymous):
What is the arc length if Θ = 6 pi over 5 and the radius is 2 cm?
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OpenStudy (anonymous):
@hartnn
hartnn (hartnn):
arc length is just \(r \theta = 2 \times 6\pi/5 = ...\)
OpenStudy (anonymous):
usE S=R*THETA here r=2cm and theta=6 pi /5 so S=(6 pi/5)*2=12pi/5=12*3.14/5=37.68/5=7.536cm
OpenStudy (anonymous):
ohhh k thanks :)
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