Question

Write the equation of a line in slope-intercept form that is perpendicular to the line y=3/5x-1 and passes through the point (-9, 4). (the 3 is on top of the 5)

Answer 1

equation of a line in slope intercept form y = mx + b
perpendicular lines the product of the slopes is -1
given the slope of the line is 3/5 then the slope of the perpendicular = -1/(3/5)= -5/3
the line passes through the point (x. y) any point on the perpendicular line and (-9, 4) known point
y-4= -5/3(x--9)
y -4+ 4 =-5/3(x) + 45/3 + 4
y = -5/3(x) + 19

Answer 2

thank you!

Answer 3

wait I have an error

Answer 4

+45/3 should be -45/3