A projectile is launched from a platform 12 feet high with an initial velocity of 104 feet per second, The height h of the projectile at t seconds after launch is given by h = –16t 2 + 104t + 12 feet. (a) How many seconds after launch does the projectile attain maximum height? (b) What is the maximum height?
have you covered quadratic equations yet?
Yes. Do we solve this just like any other quadratic using the equation?
well, notice is a quadratic equation, thus is a parabolic graph the leading term has a negative coefficient, meaning the graph is going downward thus |dw:1405124426534:dw| so if we just find the vertex of the parabola the y-coordinate wil be how high it went up x-coordinate will be how long in seconds it took to get there
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