Question

The perimeter of a rectangle is 52. If its length is 2 more than 3 times its width, find the dimensions of the rectangle.

Answer 1

hello so
if x = length of rectangle and y=width of rectangle then
2x+2y=52, as there are 2 lines of each
and
2 more than 3 times its width is length so
x=3y+2
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solve these 2 equations
2x+2y=52
x=3y+2

Answer 2

@dan815 nice explanation man...

Answer 3

first one is 26

Answer 4

width or length?

Answer 5

if you found one you can plug in and find the other

Answer 6

Are you familiar with solving system of equations?

Answer 7

width

Answer 8

its 26 @dan815 ?

Answer 9

Solve this to find out:
2x+2y=52
x=3y+2
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Answer 10

since you know x in terms of y, sub that into equation 1 and solve for y

Answer 11

2 (x) +2y=52
2(3y+2)+2y=52

Answer 12

2(3y+2)+2y=52
6y+4+2y=52
8y=48
y=6

Answer 13

x=3y+2
=3(6)+2