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The sum of three consecutive even integers is 312. Find the integers. Write the three integers in order of smallest to largest:
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x + (x+1) + (x+2) = 312 3x + 3 = 312 3x = 309 x = 103 So the three integers are: 103 104 105
but there even
"three consecutive even integers"
those are odd
you can do similar thing to wolf's work though. x + (x+2) + (x+4) = 312
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\[x+(x+2)+(x+4) = 312\] Solve for x.
156
three consecutive
cant ever be even
did you try and solve for x?
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yea hold on
x3+3=312
or is it x2+2=312
idk
none. \(x + (x+2) + (x+4)=312 \\ x+x+x+2+4=312\\3x+6=312\)
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-6
306
??
102,104 106
you got it right
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or no im 2 off
no nvm
102, 104, 106 are correct
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