Question

Exponential growth decay

Medal

Answer 1

\(\sf A_t=A_o*e^{kt}\)

\(\sf 784~insects=(223~insects)*e^{7k}\)

solve for k, \(\sf k=\dfrac{1}{7}*(ln\dfrac{784}{223})=0.1796=0.18\)

so the equation is \(\sf A_t=(223~insects)*e^{0.18t}\)

Answer 2

cool?

Answer 3

we cool

Answer 4

sweet

Answer 5

why doesn't 223*e^(.8*62) equal 15668600 insects at 62 days?

Answer 6

it's "223*e^(0.18*62)", you missed a digit in the k.

Answer 7

nah

Answer 8

@aaronq

Answer 9

i think they wanted you to use the right number of significant digits
1.5668639231281811e7 = 1.60*10^7