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Describe the nature of the roots for this equation 2x^2+5x-7=0. A.) Two real, irrational roots B.) One real double root C.) Two real rational roots D.) Two complex roots
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First get the decremental \[\sqrt{b ^{2}-4ac}\] d is the inside of the root. if it was d = 0 then one real solution. d<0 2 imaginary d>0 2 real
Sothe answer is D?
as the rule is \[\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]
it was C :(
yea it is -7 not 7
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so you get d = 81
i got -31...
You substituted wrong :P |dw:1405218136253:dw| -*- = +
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