Question

Solve: x^2 -6x + 58 = 0
A.) {3+7i, 3-7i}
B.) {2+9i, 2-9i}
C.) {7+3i, 7-3i}
D.) {2+19i, 2-19i}

Answer 1

\(x^2-6x+58=0\iff(x-3)^2=-58+(-3)^2=-58+9=-49\)
so

\((x-3)^2=-49\) can you complete it>

Answer 2

?

Answer 3

you can see the answer from there if you know what \(\sqrt{-49}=\)

Answer 4

7i?

Answer 5

right, so which one do you think it is?

Answer 6

A

Answer 7

correct

Answer 8

I completed the square, google it if you dont know it. Its not that hard and helps when there is no coefficient on the 1st term.