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OpenStudy (anonymous):
A triangle has an area of 20 cm2. The height of the triangle is three cm longer than the base. Find the height and base of the triangle.
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OpenStudy (anonymous):
help!
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
What's the general formula for the area of a triangle?
OpenStudy (anonymous):
A=hbb over
2
jimthompson5910 (jim_thompson5910):
it should be
A = (b*h)/2
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jimthompson5910 (jim_thompson5910):
"The height of the triangle is three cm longer than the base"
So,
height = base + 3
h = b+3
jimthompson5910 (jim_thompson5910):
A = (b*h)/2
A = (b*(b+3))/2
20 = (b*(b+3))/2
20*2 = b*(b+3)
40 = b*(b+3)
and I'll let you finish up
OpenStudy (anonymous):
we dont know the base ?
jimthompson5910 (jim_thompson5910):
you solve that equation to get the base
OpenStudy (anonymous):
divide
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jimthompson5910 (jim_thompson5910):
40 = b*(b+3)
40 = b^2 + 3b
0 = b^2 + 3b - 40
b^2 + 3b - 40 = 0
Now factor and solve
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
b= -8,5???
jimthompson5910 (jim_thompson5910):
toss out the negative solution, you can't have a negative base
jimthompson5910 (jim_thompson5910):
so b = 5 is the only practical solution
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jimthompson5910 (jim_thompson5910):
h = b+3
h = 5+3
h = 8
jimthompson5910 (jim_thompson5910):
b = 5
h = 8
OpenStudy (anonymous):
thanks
jimthompson5910 (jim_thompson5910):
you're welcome
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