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Mathematics 17 Online
OpenStudy (anonymous):

(x-4) (x+2)=0

OpenStudy (zzr0ck3r):

ab = 0 imples a = 0 or b = 0

OpenStudy (zzr0ck3r):

so solve x-4 = 0 and x+2 = 0

OpenStudy (anonymous):

\[\huge \color{green}{\textsf{Welcome To Openstudy...}}\]

OpenStudy (anonymous):

x-4and x+2=2xiskuwerd-8

OpenStudy (anonymous):

See, for \((x-a)(x-b) = 0\) Either first parenthesis ie \((x-a) = 0\) or second parenthesis ie \((x-b)\) = 0 So, \(x = a\) or \(x = b\)..

OpenStudy (anonymous):

l=b

OpenStudy (anonymous):

\[-30y2,45y what question\]

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