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(x-4) (x+2)=0
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ab = 0 imples a = 0 or b = 0
so solve x-4 = 0 and x+2 = 0
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x-4and x+2=2xiskuwerd-8
See, for \((x-a)(x-b) = 0\) Either first parenthesis ie \((x-a) = 0\) or second parenthesis ie \((x-b)\) = 0 So, \(x = a\) or \(x = b\)..
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l=b
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