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Mathematics 10 Online
OpenStudy (anonymous):

If f(x) = x3 – 2x2 + 3x + 5, then evaluate f(–3). Select one: a. 44 b. –22 c. –13 d. –49

OpenStudy (chriss):

just substitute in 3 for x and solve it

OpenStudy (camerondoherty):

replace x for -3 f(-3)=(-3)-2(-2)^2+3(-2)+5

OpenStudy (camerondoherty):

solve that

OpenStudy (camerondoherty):

my mistake f(-3)=(-3)-2(-3)^2+3(-3)+5

OpenStudy (shamim):

put x=-3

OpenStudy (anonymous):

c?

OpenStudy (chriss):

right, -3... my bad

OpenStudy (chriss):

not c

OpenStudy (chriss):

\[(-3)^{3}-2(-3)^{2}+3(-3)+5\]

OpenStudy (anonymous):

-25

rvc (rvc):

9-2(9)-9+5

OpenStudy (anonymous):

i mean -22

OpenStudy (chriss):

not -22

OpenStudy (anonymous):

-27-18-9+5 = -49

rvc (rvc):

9-18-9+5 -18+5 -13

rvc (rvc):

ohh ok its cube

OpenStudy (chriss):

tox is correct

rvc (rvc):

yes

OpenStudy (anonymous):

WOW, thx

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