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If f(x) = x3 – 2x2 + 3x + 5, then evaluate f(–3). Select one: a. 44 b. –22 c. –13 d. –49
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just substitute in 3 for x and solve it
replace x for -3 f(-3)=(-3)-2(-2)^2+3(-2)+5
solve that
my mistake f(-3)=(-3)-2(-3)^2+3(-3)+5
put x=-3
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c?
right, -3... my bad
not c
\[(-3)^{3}-2(-3)^{2}+3(-3)+5\]
-25
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9-2(9)-9+5
i mean -22
not -22
-27-18-9+5 = -49
9-18-9+5 -18+5 -13
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ohh ok its cube
tox is correct
yes
WOW, thx
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