Question

3. A bicyclist travels the first 700 m of a trip at an average speed of 8 m/s, travels the next 600 m in 90 s and the last 50s at a speed of 21 m/s. Find the average speed of the bicyclist for this trip.

Answer 1

help please

Answer 2

\[r=\frac{d}{t} \]\[r=\frac{700+600+50\ 21}{\frac{700}{8}+90+50}=\frac{940}{91}=10.33 \]50 21 is 50 times 21.