Question

suppose kim is choosing three letters from the alphabet randomly without replacement and without looking at the letters. what is the probability that she chooses the letters of her name in order

Answer 1

Only one such permutation (K-I-M) exists, so the probability would be 1 out of the total possible 3 letter permutations.
\[\text{total possible}={\large{}_{26}P_{3}}=\frac{26!}{(26-3)!}=26\times25\times24\]