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How many different committees can be formed from 6 teachers and 33 students if the committee consists of 3 teachers and 3 students?
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I know the combination formula, but I don't know how to combine 6C3 and 33C3 to get the answer.
\[6C3=\frac{ 6*5*4 }{ 3*2*1 }=20\] \[33C3=\frac{ 33*32*31 }{ 3*2*1 }=11*16*31=?\]
you don't "combine" them you multiply them \[\binom{6}{3}\times \binom{33}{3}\]
you got that?
Thank you!!!
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