Find the solution of five times the square root of the quantity of x plus 7 equals negative 10 and determine if it is an extraneous solution.

x = −3; extraneous

x = −3; not extraneous

x = 11; extraneous

x = 11; not extraneous

Question

Find the solution of five times the square root of the quantity of x plus 7 equals negative 10 and determine if it is an extraneous solution.

 x = −3; extraneous

 x = −3; not extraneous

 x = 11; extraneous

 x = 11; not extraneous

anonymous · Answer

Is this the equation? 

$$\Large 5\sqrt{x+7}=-10$$

anonymous · Answer

im not sure lol i hate math so much.. but probably

anonymous · Answer

Where is your question? Can you show me a picture or a screenshot?

anonymous · Answer

yeah thats the problem my bad i couldnt find it

anonymous · Answer

@doulikepiecauseidont thats the problem

anonymous · Answer

First step to this is to isolate the square root so you divide both sides by 5

anonymous · Answer

ok

anonymous · Answer

what did you get it to =?

anonymous · Answer

x+7 = -10/5

anonymous · Answer

well sqrt of x+7= -10/5 but yes,
-2=-10/5, so the next step is to square both sides to get rid of the square root, what is (-2)^2?

anonymous · Answer

idk

anonymous · Answer

what is 2 *2? that is the same as 2 squared

anonymous · Answer

1.4