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solve the equation 6x^2+11x-35
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this is not an equation
do you mean \(6x^2+11x-35=0\)?
well just help me solve it atleast
you cant solve unless you have it set equal to something
i forgot to write =0
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\(\frac{-b\pm\sqrt{b^2-4ac}}{2a}\) for you \(a=6\\b=11\\v=-35\)
Alternatively you can use factoring methods... for 6x2+11x−35=0
|dw:1405317211411:dw|
6x^2 + 21x - 10x -35 =0 and so on..
where did you get -35 from?
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so i still don't get it
is your question 6x2+11x−35=0
yes
6x2+11x−35=0 6x^2 + 21x - 10x -35 =0 3x(2x+7) -5(2x+7) =0 (3x-5)(2x+7) =0
i hope you can solve for x now...
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yes i can thank you
yw
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