Question

find dy/dx
xy^2=16

Answer 1

Let's use implicit differentiation:
x(2y)(y') + y^2 = 16
2xy(y') = 16 - y^2
dy/dx = (16 - y^2)/2xy

Answer 2

shouldnt it be -y^2/2xy

Answer 3

Sorry yes.

Answer 4

its okay and thank you :D

Answer 5

By the way you may simplify to -y/2x

Answer 6

y*-y/2*x*y

Answer 7

i was just bout to write that

Answer 8

find dy/dx of y(x+y)=4

Answer 9

\[ yx+y^2=0\]
\[dy/dx1*x+y+dy/dx2y=0\]
\[-y/x+2y\]

Answer 10

\[\frac{dy}{dx}=\frac{y}{x+2y}\]