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rewriting a fraction as a single trigonometric function
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\[(\sec x-\cos x) \div \sin x\]
anyone?
\[(secx-cosx) \div sinx=(\frac{ 1 }{\cos x }-\cos x) \div \sin x\]\[=\frac{ 1-\cos x }{\sin x \cos x }\]
I cannot see much else that can be done.
the answer says its tanx but i dont get how to get there
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sure you got the question correctly written out.
yea but ill try typing it out again in case i didnt
|dw:1405345617844:dw|
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