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the area of a rectangle is given by the equation w(2w+1)=36 what is the width of the triangle?
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First factor out w(2w+1) to get 2x^2+w=36
ok I know the answer is 4 but I need to work it out
\[2w^2+w=36\] Take square root: \[\sqrt{36}=6\] \[2w+w=6\]
\[3w=6\] \[w=2\]
but the answer should be 4 so how is it 2
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