Find the sum of the geometric sequence.

three divided by two, three divided by eight, three divided by thirty two, three divided by one hundred and twenty eight, three divided by five hundred and twelve

Question

Find the sum of the geometric sequence. 

three divided by two, three divided by eight, three divided by thirty two, three divided by one hundred and twenty eight, three divided by five hundred and twelve

aum · Answer

$\Large S = \frac 32+\frac38+\frac{3}{32}+\frac{3}{128}+...$
$\Large S = 3(\frac 12+\frac18+\frac{1}{32}+\frac{1}{128}+...)$
What is the common ratio?

anonymous · Answer

i have no idea  :/

aum · Answer

Divide the second term by the first term.

anonymous · Answer

.0625

anonymous · Answer

one divided by two hundred and fifty six

 one divided by sixteen

 one thousand twenty three divided by five hundred and twelve

 341

aum · Answer

3/8 divided by 3/2 = 3/8 x 2/3 = 1/4
$\Large r = \frac 14;~~ a = \frac 32$
$\Large S = \frac{a}{1-r}$

aum · Answer

This is sum of an infinite geometric series, right?

anonymous · Answer

yeah

aum · Answer

None of the answer choices you provided matches my answer.  Are you sure those are the answer choices for this problem and not for the previous or the next problem?

aum · Answer

Sum of the infinite geometric series = 2 for this problem.