Which point lies on the graph of the following piecewise function? y = x2 if x less than or equal to 0 y = x + 1 if x > 0 (0, 1) (-1, 0) (-2, 4) (1, 1)
@zzr0ck3r @Zarkon @aum
look at the x value. if its less than or equal to 0, plug it into x^2 else plug it into x+1 and make sure you get the same y value as in the list. example (0,1), 0 = 0 so we use the first equation x^2 pluging in 0 we get 0^2 = 0 is NOT equal to 1, so (0,1) does not lie on the ....
ok let meh plug it in and check back with ya in a sec
word
so I think A but not sure because when i plugged it in it doesn't seem to agree on one
@zzr0ck3r
@aum
@zzr0ck3r @zzr0ck3r @zzr0ck3r @zzr0ck3r @zzr0ck3r @zzr0ck3r @zzr0ck3r @zzr0ck3r
are you still there lol
look at B
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