Question

Find the slope of the line passing through the points (-3, -10) and (4, 5).

Answer 1

Slope=y2-y1/x2-x1
Now, plug in the numbers.

Answer 2

slope=change in y/change in x=(y2-y1)/(x2-x1) and here y2=5, y1=-10, x2=4, and x1=-3. We have:
slope=(5-(-10))/(4-(-3)= 15/7

Answer 3

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -3}}\quad ,&{\color{blue}{ -10}})\quad &({\color{red}{ 4}}\quad ,&{\color{blue}{ 5}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\)