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solve for x: x^2-2x-15=0 is ? please help
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two numbers that multiply to get -15 and add to get -2 are ?
-5 and -3
-5*-2=15 -5+-2=-7
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one of them should be negative. which one?
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-5 plus 2
(x-5)(x+3)
x=5 and x= -3
solve step by step
\(-5\) and \(3\) then we expand the middle term \(x^2-2x-15=0\) becomes \(x^2-5x+3x-15=0 \iff x(x-5)+3(x-5)=0\iff (x+3)(x-5)=0 \\ \iff x=-3 \ \text{or } x=5\)
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would you write it again
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