Question

for the function y=4(x^2-5x), find the value of the dx/dt when x=1 and dy/dt=5


find the derivative of y=xsinx

can someone explain and show how you do one or both

Answer 1

\[y=4\left( x^2-4x \right),\frac{ dy }{ dt }=4\left( 2 x \frac{ dx }{ dt }-4\frac{ dx }{ dt } \right)\]
x=1,\[\frac{ dy }{ dt }=5,put ~these~ values ~and~ find ~the~ value~ of~\frac{ dx }{ dt }\]