Help.
1. Solve the compound inequality, showing your work. Name the solution set and then draw the graph of the solution set. y-2< -5 or y->5
For the right one, you will want to +2 to both sides, so the y is isolated
*left Sorry
for the right one you have to move the (-) over....
Like this x-2 > 5 or x-2 <-5... bekum abs(x-2)>5 or abs(x)>7
x-2>5 x>7 and x-2<-5 X<-3
so it will be a close or open on the graph on -3 and 5
\(\Large OpenGraph\)
\(\Large Medal~Pls\)
it is always open when dealing with infinities and non-equality such as less than or equal to or greater than or equal to
okay
so its -3 and 5
i don't know I didn't check you should be able to check if your answer is correct or not
I don't think that the right hand side of the inequality was written correctly
you can't have that kind of inequality
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