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lim sin2x/sinx x--->0
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well us the substitution sin(2x) = 2sin(x)cos(x) then see what happens...
that's an identity ? never knew that.
ok.... its a double angle identity
okay i got it is 2, thanks! ;D
is the question 1. \[\frac{\sin(2x)}{\sin(x)}\] or 2. \[\frac{\sin^2(x)}{\sin(x)}\]
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1 lol
i know how to make an exponent lol
ok...
thank you though you helped me
how about sin4x/sin3x ?is there an identity for that lol
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