Question

solve following equation for values of theta in range of................., in terms of pi

Answer 1

@ikram002p

Answer 2

\[7\tan2x = 4sinx\]

Answer 3

Try solving this equation manually

Answer 4

The book answer is
0, 0.580pi, pi, 1.420pi, 2pi

Answer 5

@PFEH.1999

Answer 6

is it like this ?

\(\Huge 7 \tan 2x = 4 \sin x \) for 0≤x≤2π

Answer 7

yes

Answer 8

nw
tan 2x= ?

Answer 9

it has identity do you know it ?

Answer 10

\(tan(2x) = [2 tan(x)] / [1 - tan^2(x)] \)

Answer 11

ok..

Answer 12

tan(2x) = [] / [1 - tan^2(x)]
\[\Huge tan(2x) =\dfrac { 2 \tan(x) } { 1-\tan^2 (x) }\]

Answer 13

so
\(\Huge 4\sin x =7 \dfrac { 2 \tan(x) } { 1-\tan^2 (x) }\)

Answer 14

\(\Huge 4\sin x(1-\tan^2 (x) ) = 14 \tan(x) \)

Answer 15

ok..