Find the value of x.

AD = 2x + 4
DB = 6x - 20

http://image.tutorvista.com/content/feed/tvcs/diagonalrectangle45.JPG

Question

Find the value of x.

AD = 2x + 4
DB = 6x - 20

http://image.tutorvista.com/content/feed/tvcs/diagonalrectangle45.JPG

anonymous · Answer

nope it was just that...

abmon98 · Answer

$$(6x-20)(6x-20)=(2x-4)(2x-4)+AB^2$$$$36x^2-120x-120x+400=4x^2-8x-8x+16+AB^2$$$$(36x^2-4x^2)+(-240x+16x)+(400-16)=AB^2$$
$$32x^2-224x+384=AB^2$$
$$x^2-7x+12=AB^2$$
$$(x-3)(x-4)=AB^2$$
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anonymous · Answer

that's the only thing given sorry o-o

abmon98 · Answer

@Anime_Basics i made a mistake 
i wrote (2x-4) instead of writing (2x+4)
(2x+4)(2x+4)+AB^2=36x^2-240x+400
4x^2+8x+8x+16+AB^2=36x^2-240x+400
32x^2-256x+384=AB^2
x^2-8x+12=AB^2
sqrt(x^2-8x+1)=AB

abmon98 · Answer

(x-2)(x-6) and square root 6 and 2