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solve the inequality x^2-x-12>0
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x-12>0 add 12 to both sides x>12
Got it @dianaeshun
x^2-x-12 > 0 treat as an equation and find nullifying X x^2-x-12 = 0 factor or solve using a quadratic eqaution: x=-3, x=4 since x^2 is a positive, it's a "smiling" parabola (positive) and since the problem asked for everything bigger than 0 the answer is x<-3 OR x>4
|dw:1405435255887:dw|
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