Question

using complex numbers and its properties show that Sin^7 [θ] = 1/64 (35 Sin[θ] - 21 Sin[3 θ] + 7 Sin[5 θ] - Sin[7 θ])

Answer 1

don't remember properties of complex numbers
would suggest expressing sin^7 {0} differently

Answer 2

@hero@zzr0ck3r @zepdrix@Compassionate can you help

Answer 3

I do recognize that you have a pattern
let n = 7
1/2^(n-1)