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What is the simplified form of the quantity y-squared plus 2y minus 8 over the quantity y-squared plus 7y plus 12 ?
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\[\frac{y^2+2y-8}{y^2+7y+12}\]We have to find the roots\[y^2+2y-8=0\]Roots\[y_1=-4~~and~~y_2=2\]And the second\[y^2+7y+12=0\]Roots\[y_3=-4~~and~~y_4=-3\]Now we can write this function\[\frac{(x+4)*(x-2)}{(x+4)*(x+3)}\]Simplifying\[\frac{(x-2)}{(x+3)}\]
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