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modus ponen
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Question ?
let p = F let q = T \[(p \rightarrow q) \wedge p = ?F?\] \[p \rightarrow q = T \wedge T = T\]
What about it?
shouldn't it be T instead of F ?
\[ \land p = \land F = F \]
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p ^ q is only true if BOTH p and q are true if one is false, then the entire thing is false
it's ^q
pellet nevermind
HAHA I am fkin blind right now
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it's p not q haha
lol
funniest guy on openstudy ^^^
In case he tries to erase it:
hahahah
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if you lose those I got backups...
lol
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