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resolve into factors y^4+2y^3z-2yz^3-z^4
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is this algebra 1 or 2?
all you have to do is factor.
do want me to teach you how to factor or do you already know how?
\(\Large y^4+2y^3z-2yz^3-z^4=(y^4-z^4)+(2y^3z-2yz^3)\\\Large =(y^2+z^2)(y^2-z^2)+2yz(y^2-z^2)\\\Large =(y^2-z^2)(y^2+z^2+2yz)\\\Large =(y^2-z^2)(y+z)^2\)
excellent work
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:) thanks
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