ive been workin on this problem for an hour and is realy starting to tick me off. please help me. http://media.education2020.com/evresources/2004-06-01-03-00_files/i0380000.jpg Find the surface area of the regular hexagonal pyramid. Round your answer to the nearest hundredth.
still need help??
yea. i watched some videos to try to help but i get something thats not one of my answers.
i kniow its not 115.14ft^2
I draw the base first, |dw:1405518258445:dw|
by pythagorean, show me OA=??
3.99??
why not 4 ?? but 3.99??
i didnt round.
\[OA^2 = OC^2+AC^2 =(2\sqrt3)^2+2^2=12+4 =16\\OA =4\], it's not rounded answer
sqrt3 *2 * itself gave me 11.99 2^2 gave me 4 added together then the sqrt i got 3.99
either way its 4
so how do i find the rest?
Yea, song6 does the rest for you:) hihihi, just a little bit hard to read.
i cqant read it -__-
Let the top of the pyramid is H, you link HO, then you can see the right triangle HOA have OA =4 (proof above) and, the slant HA=6(given), you can find HO which is the height of the pyramid, show me your answer for HO
where are you putting the letters? look im really confused and really pissed at this stupid thin. its steadily aproachion 2 hours on this stupid problem and im about to say screw this.
and im dyslexic aoparetnly or i just cvant type to save my life haha..
|dw:1405519061604:dw|
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