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The diagram shows the curve y=(4-x)^ex and its maximum point M. the curve cuts the x-axis at A and the y-axis at B write down the co-oordinates of A and B Find the x-coordinate of M The point P on the curve has x-coordinates of P the tangent to the curve at P passes through the origin O calculate the value of p(the x-coordinate).
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Question 18 i solved part 1 i got the coordinates of A and B
First, you mean the curve y=(4-x) e^x (not y=(4-x)^ex) M looks like the peak of the curve, where the slope of the curve is "flat" (i.e. zero) find dy/dx and set it equal to zero. solve for x
for point P, we use this idea: |dw:1405530642531:dw| the slope is also the derivative
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