Question

expand (c^4-2b^2)^3 using the factor formula (x-y)^3
A. c^12-6c^8b^2+12c^4b^4-8b^6
B.c^12+6c^8b^2+12c^4b^4+8b^6
C.c^12+3c^8b^2+3c^4b^4+8b^6
D.c^12-6c^8b^2-12c^4b^4-8b^6

Answer 1

@PFEH.1999

Answer 2

@PFEH.1999

Answer 3

well,first we need to know what is (x-y)^3, you can find it bu multiplyng these: (x-y)(x-y)(x-y) and it would be : x^3- 3x^2y +3xy^2- y^3

Answer 4

ok i need the answer i hve 3 more ? i only have 10 min

Answer 5

ok,we can solve three questions in three minuts..i'm sure ;)

Answer 6

whats the answer to this one

Answer 7

so we just need to imagine that c^4 is x and 2b^2 is y and we simply can write:
c^12 - 6c^8b^2 + 12c^4b^4 + 8b^6 so simply,A is the answer ;)

Answer 8

match each expression with the equicalent expressions
A.2x^2-20+47
B.2x^2-20x+53
C.2x^2+20x+50
D.2x^2+20+53



match there with the right one
1.2(x-5)^2+3
2.2(x+5)^
3.2(x+5)^2+3
4.2(x-5)^2-3

Answer 9

gtg be bak on at 2

Answer 10

number 1 = 2x^2 + 50 - 20x + 3 so it matched B so 1-->B

number 2 : i don't really know what does 2(x+5)^ mean...i think you've missed something.

number 3 = 2x^2 + 50 + 20x + 3 and it seems D is 20x not B and in this case n3 would be matched to S

number 4 = 2x^2 + 50 - 20x - 3 and it simply matched A (and here again 20 should be changed to 20x)

Answer 11

sry i have to go...i'm veryy sry i'll be back for about 1 hour!