Question

Given the coordinates of the vertices of triangle RST are R(-3, 5), S(4, 5) , and T(4, -2). What is the measure of side RT to the nearest tenth?

7.0
9.9
8.2
6.8

Answer 1

do you know the distance formula?

Answer 2

d/t?

Answer 3

\[\sqrt{(x _{1}-x _{2})^{2}+(y _{1}-y _{2})^{2}}\]

Answer 4

Oh yes! I remembered.

Answer 5

now plug int he points for R and T

Answer 6

On it!

Answer 7

42

Answer 8

how did you get 42?

Answer 9

\[\sqrt{(-3-4)^{2}+[5-(-2)]^{2}}\]

Answer 10

That's what I did :)

Answer 11

\[=\sqrt{(-7)^{2}+7^{2}}\]

Answer 12

\[=\sqrt{49+49}\]

Answer 13

9.8?

Answer 14

you shouldve gotten 9.899...
and round up to 9.9

Answer 15

@nikato do you have another time for a problem?

Answer 16

yea. sure

Answer 17

I did this. But not quite sure which one is the answer. I think it was A.

Answer 18

Or C..

Answer 19

no.
what ratio did you get?

Answer 20

I got 3/22 or 3:22

Answer 21

As I remembered. You want me to find the question?

Answer 22

I'll tag you in the link of it.

Answer 23

yes.
so its A.
because they have the ratio.
PQ and NM are paraellel

Answer 24

and find what question?

Answer 25

Oh just to show you the same question I asked before. Thank you again!

Answer 26

no problem