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Determine the solution to the system of equations given below. y=x^2-6x+10 y=-x+4 A.(2,3) B.(3,1) C.(2,2) and (3,1) D. no solution
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use substitution :)
Try solving them: \[\Large -x+4=x^2-6x+10\]
Get it equal to zero: \[\Large 0=x^2+5x+6\] Factoring anyone?
Whoops, *-5x not +5x
Is x=-1
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it will turn into a quadratic equation
\[x ^{2}-5x +6=0\]
I got (3,2)
c
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