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finding the relative extrema 6x+lnx
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take the derivative set it equal to zero solve for\(x\)
would it be 1/2(6x) or 1/2(6)
because Lnx = 1/x
\[y=6x+\ln(x)\\ y'=6+\frac{1}{x}\\ y'=\frac{6x+1}{x}\]
now set it = to 0 ?
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x=-1/6
yes
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