Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

Can someone check this for me? The lab results were Evaporating Dish 24.35g NaCHO3 37.06 (includes evaporating dish) HCI 40.06g (includes evaporating dish) The question is : 3. The NaHCO3 is the limiting reactant and the HCl is the excess reactant in this experiment. Determine the theoretical yield of the NaCl product, showing all of your work in the space below. My answer is : NaCHO3: 37.06g - 24.35g = 12.71 g NaHCO3 1 mol NaHCO3 & 1 HCl --> 1 mol NaCl & 1 H2O & 1 CO2 12.71 g NaHCO3 @ 58.44 g/mol NaCl / 84.01 g/mol NaHCO3 = 8.841 grams of NaCl

OpenStudy (donblue22):

This question belongs in chemistry

OpenStudy (anonymous):

seems right everything is balanced

OpenStudy (anonymous):

oops sorry I thought I clicked chemisty! Thank you though (x

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!