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let an=na n-2,with a1=1and a2=2.then a4a3 equals A.12 B.24 C.2 D.7
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\[a_n=na_{n-2}\] with \[a_1=1,a_2=2\]?
thats correct i just couldnt type it like that
that is my guess in any case first you need \(a_3\) which is \[3\times a_{3-2}=3\times a_1=3\times 1=3\]
ok
then you need \(a_4\) which is \[4\times a_{4-2}=4a_2=4\times 2=8\]
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ok , can u help me solve the rest
what is left to do?
im confused
you were asked for \(a_3\times a_4\) right?
yes
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we found \(a_3=3,a_4=8\) all that is left for you is to multiply
so it would be 3x8=24
@satellite73 can u help me with absolute value
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