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Mathematics 14 Online
OpenStudy (anonymous):

8^C4

OpenStudy (mathmate):

Do yo mean \(C^8_4\)?

OpenStudy (anonymous):

No, it's finding combinations

OpenStudy (mathmate):

So you are looking for the number of ways of choosing 4 out of 8 different objects? Yes, this is combinations, we call it 8 choose 4, or 8C4, or \(C^8_4\), or \(\left(\begin{matrix}8 \\ 4\end{matrix}\right)\)

OpenStudy (mathmate):

In general, the formula is nCr=n!/((n-r)!r!) where ! stands for factorial.

OpenStudy (anonymous):

Thanks

OpenStudy (mathmate):

You're welcome! :)

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